Function as.function.permutation() in the permutations package: group actions
Author: Robin K. S. Hankin

# Function `as.function.permutation()` in the permutations package: group actions

#### Robin K. S. Hankin

    as.function.permutation

    ## function (x, ...)
    ## {
    ##     a <- NULL
    ##     x <- as.matrix(as.word(x))
    ##     if (nrow(x) == 1) {
    ##         return(as.function(alist(a = , x[, a])))
    ##     }
    ##     else {
    ##         return(as.function(alist(a = , x[cbind(seq_len(nrow(x)),
    ##             a)])))
    ##     }
    ## }
    ## <bytecode: 0x64414f1c07b0>
    ## <environment: namespace:permutations>

To cite the permutations package in publications, please use Hankin (2020). The `permutations` package was intended to manipulate and combine permutations, but often one wants to consider the effect of a permutation on the underlying set, taken to be \(\left[n\right]=\left\lbrace 1,2,\ldots,n\right\rbrace\). In other words, we wish to consider a permutation as a function. In package idiom, coercing a permutation to a function is straightforward:

    g <- as.cycle("(45)(127)")
    as.function(g)(4)

    ## [1] 5

Above we see that permutation \((45)(127)\) maps 4 to 5. We can see from the function body, at the top of the page, that permutations are coerced to word form. Function `as.function.permutation()` uses `as.matrix()` to stop “`x[a,]`” dispatching to `[.word()` and use matrix extraction instead. It might be argued that `unclass()` would be better coding.

Coercion is vectorized:

    as.function(g)(1:7)

    ## [1] 2 7 3 5 4 6 1

    as.function(allperms(4))(3)

    ##  [1] 3 4 2 4 2 3 3 4 1 4 1 3 2 4 1 4 1 2 2 3 1 3 1 2

    as.function(rperm(7,8))(1:7)

    ## [1] 6 2 2 7 3 2 2

The second and third forms use the `alist(a = , x[cbind(seq_len(nrow(x)),a)])` construction. We now discuss the extent to which the underlying permutation group is represented in package idiom. Consider the following construction:

    (p <- cyc_len(2))

    ## [1] (12)

    as.function(p)(3)

    ## Error in x[, a]: subscript out of bounds

On the one hand, object `p` is a permutation on the set \([2]=\left\lbrace 1,2\right\rbrace\). The action of this permutation on 3 is not defined, and the package returns an error. Above we effectively see

    t(1:2)[,3]

    ## Error in t(1:2)[, 3]: subscript out of bounds

which is the origin of the error. On the other hand, one might reasonably hold that the action of \((12)\) on 3 should be 3, on the grounds that \((12)\) transposes elements 1 and 2 and leaves all other elements unchanged. To realise this interpretation we need to ensure that `p` has underlying set including 3, in this case \(\left\lbrace 1,2,3\right\rbrace\). This is straightforward with `as.word()`:

    as.function(as.word(p,n=3))(3)

    ## [1] 3

### Note on identity permutation

The ever-problematic identity permutation acts on the empty set so its functionalization always returns an error:

    as.function(id)(4)

    ## Error in x[, a]: subscript out of bounds

Again the resolution is to coerce to word form with explicit `n`:

    as.function(as.word(id,n=4))(4)

    ## [1] 4

### References

Hankin, R. K. S. 2020. “Introducing the Permutations R Package.” SoftwareX 11. https://doi.org/10.1016/j.softx.2020.100453.